Friday, January 11, 2008
Thursday, January 10, 2008
Chaining the Inner Beast
Hi this is my scribe (despite the odd title)!
Hope you enjoyed!
The next scribe will be....
Mark!
Hope you enjoyed!
The next scribe will be....
Mark!
Wednesday, January 9, 2008
scribe number six.
Hello today's class was a very short class due to Mr. K's absence for most of the class. He had to attend a meeting. I am lucky that I do not have to do a very lengthy scribe.
Mr. K started off by asking us if this was true:
[see slide two for original slide.]
We then found out that it was not true. After that Mr. K asked us if we knew what derivative rule would give us a product in the for its derivative. We figured out that the chain rule would do just that. So instead of differentiating the function we would anti-differentiate it by running the chain rule backwards. Remember: the chain rule involves a composite of functions and do not forget to add the constant.
So to test this out Mr. K gave us a number of problems to work on. The first three problems were pretty straight forward. All that had to be done was to run the chain rule backwards. The last three problems were a little bit different. There must be a product in order to run the chain rule backwards. If there isn't a product you can just simply multiply by the number one but you need to be clever about it. Here is an example[see slide three for original slide]:
The last three problems were similar to the example shown above. Shortly after that, Mr. K departed to his meeting and Ms. Pangan came in to supervise us. We were assigned eleven question 1-21 odds only! If you did not finish those in class it is for homework. We also used the smartboard but it froze and somehow got disconnalcted [Chris' word] [disconnected]! but have no fear Craig saved the day and fixed it ! ZING! After that he successfully powered it off! I'm not quite too sure who has been scribe yet so I will ask in class and decide from there.
Mr. K started off by asking us if this was true:
[see slide two for original slide.]
We then found out that it was not true. After that Mr. K asked us if we knew what derivative rule would give us a product in the for its derivative. We figured out that the chain rule would do just that. So instead of differentiating the function we would anti-differentiate it by running the chain rule backwards. Remember: the chain rule involves a composite of functions and do not forget to add the constant.So to test this out Mr. K gave us a number of problems to work on. The first three problems were pretty straight forward. All that had to be done was to run the chain rule backwards. The last three problems were a little bit different. There must be a product in order to run the chain rule backwards. If there isn't a product you can just simply multiply by the number one but you need to be clever about it. Here is an example[see slide three for original slide]:
The last three problems were similar to the example shown above. Shortly after that, Mr. K departed to his meeting and Ms. Pangan came in to supervise us. We were assigned eleven question 1-21 odds only! If you did not finish those in class it is for homework. We also used the smartboard but it froze and somehow got disconnalcted [Chris' word] [disconnected]! but have no fear Craig saved the day and fixed it ! ZING! After that he successfully powered it off! I'm not quite too sure who has been scribe yet so I will ask in class and decide from there.Monday, January 7, 2008
Mondays Post
First things First, I want to say happy holidays to everyone who sees this blog :) hope you had a good vacation.
I still don't know how to do those fancy slide show stuff so my post is going to be old school writing
We were then given some questions.
and some more questions, lets take a look at this next question.
For this one I imagine the question (6+9)/3 this we can break down into (6/3) + (9/3) then reduce that down to 2+3= 5 If you look at the red, he does the exact same thing as the question I imagined. Remember that this is a integral as it is in a closed interval.
The rest of these questions use the same method, remember the chart above with the rules of finding anti derivatives.
So one last time have a great New Year.
I still don't know how to do those fancy slide show stuff so my post is going to be old school writing
The first thing we did in class was to review the work we were getting into before the break began. that means reviewing finding the anti derivatives, and the rules that go with them. We also got into definite integrals and indefinite integrals.
We were then given some questions.
and some more questions, lets take a look at this next question.
For this one I imagine the question (6+9)/3 this we can break down into (6/3) + (9/3) then reduce that down to 2+3= 5 If you look at the red, he does the exact same thing as the question I imagined. Remember that this is a integral as it is in a closed interval.
The rest of these questions use the same method, remember the chart above with the rules of finding anti derivatives.
So one last time have a great New Year.
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