April 15 Post

Next Scribe for me

Grrrr.. Can't do slideshow

bob

this unit was just the same as the rest. im still trying to catch back up. thanks to GreyM I think i will be able to do just that. Im putting more effort into cathing backup now so i hope i do good.

Pre-Test blog (Gearing Up)

what do you know I made it back for class :)

Sorry but i forgot about scribe until tonight, but all Im going over is the Pre-test. Nothing else really happened...I believe.

Personally i needed the pre-test because they was somethings I didnt even realize I didnt know and now I have the chance to look over it again.

Now on to the pre-test.

It was made up of 6 questions. Ill be going over each of the questions.

Heres the questions. All the work is done on the pages itself.

Most of these are for me to rework them so sorry if something seems really obvious.

bobing

I found this unit a bit of work to do. I missed 2 classes so I had to do catch up work. I found this unit a bit of a problem because the problems dont click in right away. I know the steps but cant carry through with the first step required to solve it,if that makes any sense. anyways good luck to everyone writing tomorrow.

Mondays Post

First things First, I want to say happy holidays to everyone who sees this blog :) hope you had a good vacation.


I still don't know how to do those fancy slide show stuff so my post is going to be old school writing

The first thing we did in class was to review the work we were getting into before the break began. that means reviewing finding the anti derivatives, and the rules that go with them. We also got into definite integrals and indefinite integrals.

We were then given some questions.and some more questions, lets take a look at this next question. For this one I imagine the question (6+9)/3 this we can break down into (6/3) + (9/3) then reduce that down to 2+3= 5 If you look at the red, he does the exact same thing as the question I imagined. Remember that this is a integral as it is in a closed interval.

The rest of these questions use the same method, remember the chart above with the rules of finding anti derivatives.So one last time have a great New Year.

extremely late scribe for Friday

Sorry about this extremely late scribe but I've been busy these last few days. What lies beneath the accumulation function? that is the question and the answer is not presents!



We were given F(t)=t as a function and have to find A(x) if A(x)= the derivative of F(t) on the interval 0 to x. We had to find the area under the F(t) and it turned out that A(x) was the parent function of F(t).



The second fundamental theorem of calculus states: if f is a continuous function on the interval [a,b] and an accumulation function is defined as the derivative of F(t) on the interval [a,x] then A'(x)= F(t).



He then gave us the question A(x) = derivative of sin(t) on the interval [1,x^2] and we have to find A'(x).
The answer is sin(x^2)*(2x)
Why?
You have to find the derivative of t on the intervals [1,x^2] then plug it in and then find the derivative of x.

Reason why, because Accumulation functions are Composite Functions.

Il try to get around to upgradeing my scribe with pics if anyone reminds me :)
Thats all

BoB

i think i put down the right unit, if i messed up let me know. this is my bob, im slowing getting back into math, thanks to my schedule at home to do homework its going a bit faster. i Believe i get everything in this unit pretty much, i want to be able to know more about the mean theorm value or what ever its called. sry about last miniut teach, but i was busy. anyways i hope everyone does good and thanks again to GreyM for helping me study and putting up with all my questions :P peace

Mondays post :)

First off before I begin, I don't know what this unit is, is it still the same? If you know put it in the chat so I can label this correctly. Now lets begin :)

Word of the day:

Gular- of or relating to the throat.

We watched a video in the beginning of class. I don't know the link or how to get it but it shows us about the graph of f(x) and a little about how f'(x) applies to it. Here's a pic of the graph in the video.

In class we only did three questions. Its all about finding the zeros of the derivative to find out is min/max critical points, and if they are local or global.

Here is the first question, its pretty straight forward. To find critical points find the root(s) of the derivative, which is 2. Put it on the number line to find out min or max, since its a restriction you have to find those too. Plug those into the the parent function to find their value and to determine global max since we already have the global min. (min = minimum) (max = maximum)

Next question. Same thing, all the detail is on the Pic :)

And last but not least the last question. Same thing and once again all details should be on it.

The next scribe is I got no idea, GreyM your stuck tomorrow at lunch with me :) and that's it

BoB

WOOT crazy episode of deal or no deal :)

first time bob ing so i hope this is right.
the unit was okay for me, better then previous experiences. I believe I'm starting to catch up and close the 2 year gap (last time I did math was in grade 10). I hope I do good on the test, as for fundementals I believe I got them all down.

peace, I love u GreyM :)
good luck all

Today's Post OF Wednesday

Umm first i hate hump day so I'm not the happiest, second I was kinda counting on the slides from today so I will not do the best job ever. Sorry guys. Oh and if you want to tutor/mentor then you should go see teach man right away. It sounds cool with good experience and can be used as a reference to your skill in the future. And it might possible be worth a credit (check me on this.)


Hate to say this but I never wrote down the questions (just the work, bad habit), Il try to get them tomorrow if anyone wants.

ps. I don't use computer much for this stuff so I don't know how to get fancy so some stuff is in brackets.


Why surface area = 4(pie)r(squared) of any sphere
If you think of a baseball if you take it apart at the seems, it makes 4 circles.
Better detail down below. Sorry i felt like experimenting.


Anyways that's all I got. Have a good night. Peace :)

Monday's Scribe (this is monday right?)

Hi, I'm tired and might make a few mistakes to bear with me please and if you something wrong let me know by email or facebook.

The teach gave us this question. We had to try to find the derivative of f(x) g(x).

multiplying the derivatives didn't give us the right answer. so we had to find a new way of find derivatives. We learned of 2 ways, that revolve around this formula.

This next slide is the classic formula. The basis of this formula is that you add and subtract same number so its like adding a zero.

After you add the "zero" you want to write out the whole equation.

You want to single out f(x+h) and g(x)

You the want to find n as it goes to zero for each part of the equation. And as n goes to Zero the equation g(x+h)- g(x) is the same as g'(x). Rewriting the equation by putting in g'(x) and f'(x) gives you your formula.

Sorry if its not that clear. Now the second way of doing it is the non traditional proof. Basically you can think of it as two rectangles. And all your doing is finding the difference between them. Take the differences, add them up and divide all that by h as h goes to zero. Remember that since h will be zero anything times to h will also be zero so therefore g'(x) f'(x) times h will be zero.

This is the whole procedure, have fun with it.

Now we had to do this all over again except this time with dividing.

As you can see we once again need a new formula.but this time there is only one.

There is the the method of doing that and to end class we did a question(below).

I know this is not the best, but its all you will get for now. :) The next scribe will be........Robert? i can't tell who's done it or not by the scribe list.

Oh yea before I forget here is one of the sites the teach used in class. I managed to copy it down.

http://archives.math.utk.edu/visual.calculus/2/product_rule.5/1.html

And lets not forget the little ditty we learned.

low de high minus high de low, all over low low :) have fun with it.